C++ Program code for Secant Method

This is the solution for Secant Method using C++ Object Oriented Aproach.

#include <iostream>
using namespace std;

class solveForRoot
{
    public:
        solveForRoot();
        void askQuadEqn();
        void askPoints();
        double f(double x);
        void findX2();
        void findError();
        void solve();
        void display();
    private:
        double x0,x1,x2,Error,a,b,c;
};
solveForRoot::solveForRoot()
{
    Error = 99;
}
void solveForRoot::askQuadEqn()
{
    cout.setf(ios::fixed,ios::floatfield);
            cout.precision(4);
            cout << "Enter a,b,c of ax^2+bx+c = 0: " ;
            cin >> a >> b >> c;
}

void solveForRoot::askPoints()
{
    cout << "Enter two points: " ;
    cin >> x0 >> x1;
}

double solveForRoot::f(double x)
{
    return a*x*x+b*x+c; // solves all equation of the form a*x*x+b*x+c;
}

void solveForRoot::findX2()
{
    x2 = x1 - (f(x1)*(x1-x0))/(f(x1)-f(x0));
}

void solveForRoot::findError()
{
    Error = (x2-x1)/x2;
        if(Error < 0)
            Error = -Error;

}

void solveForRoot::solve()
{
 cout << "x0\t" << "x1\t" << "x2\t" << "f(x0)\t" << "f(x1)\t" << "f(x2)\t" <<
 "Error\t" << endl;
    while(Error >= 0.00009)
    {
        findX2();
        findError();
        display();
        x0 = x1;
        x1 = x2;
    }
    cout << endl << endl;
    cout << "The value of root is : " << x2 << endl;
}

void solveForRoot::display()
{
 cout << x0 << "\t"<< x1 << "\t" << x2 << "\t" << f(x0) << "\t" << f(x1)
 << "\t" << f(x2)<< "\t" << Error << endl;
}

int main()
{
    solveForRoot no1;
    no1.askQuadEqn();
    no1.askPoints();
 no1.solve();

    return 0;
}